secant method help matlab

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dulanga
dulanga on 21 Sep 2014
Commented: Alberto on 22 Sep 2014
hi i have been asked to make a function file for secant menthod
fxi=f(xi);
fxi_1=f(xi_1);
% Initialize iteration count iter = 1;
%iteration for the secant starts while abs(fxi)>precsion
xi=xi-(fxi/fxi_1);
xi_1=(xi-f(xi).(xi_1-xi))/(f(xi_1)-f(xi))
% Increment the iteration count by 1
iter = iter + 1;
end %the final xr value is the root root=xi; % The total iteration number iter = iter - 1; this what i have done
when i run the values its gives this error(Attempted to access f(2); index out of bounds because numel(f)=1.) can anyone help ?
  1 Comment
Alberto
Alberto on 22 Sep 2014
I think your code interpret f, not as a function, but as an array with values. So, when you are trying to evaluate f(x), where x=2, your code looks for the second values in an array f.
Advice: 1) save your bound points in variables a and b (for example). Also create a proper function f (inline function or m-file function), so you can evaluate f in a and b. You will need a while or for+if to make your iterations.

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