How can generalize severel "For loop" ?

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STamer
STamer on 20 Feb 2013
for i=1:n
L(i,i)=1;
end
for i=2:n
L(i,1)=A(i,1)/A(1,1);
end
for i=3:n
L(i,2)=A(i,2)/A(2,2);
end
for i=4:n
L(i,3)=A(i,3)/A(3,3);
end
  2 Comments
Mark Whirdy
Mark Whirdy on 20 Feb 2013
Edited: Mark Whirdy on 20 Feb 2013
Hi there
What are the values of A & n?
Could you values for all variables and the required output as well as describing what you are trying to do?
José-Luis
José-Luis on 20 Feb 2013
This is the second time in less than an hour that the same question has been asked in the forum. Looks like the instructor recommended Matlab answers. This can be done in a rather straightforward way. Please read the "Getting started" part of the documentation and ask specific questions whenever you encounter problems. People will be happy to help you then.

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Accepted Answer

Sean de Wolski
Sean de Wolski on 20 Feb 2013
Use a nested for loop:
for ii = 1:n
for jj = ii:n
stuff
end
end

More Answers (1)

STamer
STamer on 20 Feb 2013
A=input('Enter nxn matrix:')
B=input('Enter solution matrix(n*1):')
[n n]=size(A);
L=zeros(n);
for i=1:n
L(i,i)=1;
end
for i=2:n
L(i,1)=A(i,1)/A(1,1);
end
for i=3:n
L(i,2)=A(i,2)/A(2,2);
end
for i=4:n
L(i,3)=A(i,3)/A(3,3);
end

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